Idahun kiakia: Bawo ni o ṣe ṣe afihan laini nth ni Lainos?

How do I print the nth line in Linux?

M~N with “p” command prints every Nth line starting from line M. For example, 3~2p prints every 2nd line starting from 3rd line as shown below.

Bawo ni o ṣe ka laini nth ni Unix?

N is the line number that you want. For example, tail -n+7 input. txt | head -1 will print the 7th line of the file.
...

  1. tail -n+N | head -1 : 3.7 sec.
  2. head -N | tail -1 : 4.6 sec.
  3. sed Nq;d : 18.8 sec.

How do I print the nth line of a file?

Kọ iwe afọwọkọ bash lati tẹ laini kan pato lati faili kan

  1. awk : $>awk '{if(NR==LINE_NUMBER)' tẹjade $0}' file.txt.
  2. sed : $>sed -n LINE_NUMBERp file.txt.
  3. ori: $>ori -n LINE_NUMBER file.txt | iru -n + LINE_NUMBER Nibi LINE_NUMBER wa, nọmba ila wo ni o fẹ lati tẹ. Awọn apẹẹrẹ: Tẹjade laini kan lati faili ẹyọkan.

Bawo ni MO ṣe grep faili ni Linux?

Bii o ṣe le lo aṣẹ grep ni Linux

  1. Ilana Ilana Grep: grep [awọn aṣayan] PATTERN [FILE…]…
  2. Awọn apẹẹrẹ ti lilo 'grep'
  3. grep foo /file/name. …
  4. grep -i “foo” /file/name. …
  5. grep 'aṣiṣe 123' /file/name. …
  6. grep -r "192.168.1.5" / ati be be lo / ...
  7. grep -w “foo” /file/name. …
  8. egrep -w 'word1|word2' /file/name.

Bawo ni MO ṣe grep nọmba laini kan pato ni Linux?

Aṣayan -n (tabi -ila-nọmba). tells grep to show the line number of the lines containing a string that matches a pattern. When this option is used, grep prints the matches to standard output prefixed with the line number.

Kini lilo awk ni Linux?

Awk jẹ ohun elo ti o jẹ ki olupilẹṣẹ kan kọ awọn eto kekere ṣugbọn ti o munadoko ni irisi awọn alaye ti o ṣalaye awọn ilana ọrọ ti o yẹ ki o wa ni laini kọọkan ti iwe kan ati iṣe ti o yẹ ki o ṣe nigbati a ba rii ere kan laarin ila. Awk ti wa ni okeene lo fun ilana Antivirus ati processing.

Bawo ni MO ṣe pin okun kan ni bash?

Ni bash, okun kan tun le pin laisi lilo oniyipada $ IFS. Aṣẹ 'readarray' pẹlu aṣayan -d ti lo lati pin data okun. Aṣayan -d ni a lo lati setumo ohun kikọ oluyapa ninu aṣẹ bii $ IFS. Pẹlupẹlu, lupu bash ni a lo lati tẹjade okun ni fọọmu pipin.

Aṣẹ wo ni yoo tẹjade gbogbo awọn ila ninu faili naa?

Awọn laini titẹ sita lati Faili kan nipa lilo sed

sed "p" pipaṣẹ jẹ ki a tẹjade awọn ila kan pato ti o da lori nọmba laini tabi regex ti a pese. sed pẹlu aṣayan -n yoo dinku titẹ sita laifọwọyi ti saarin apẹẹrẹ/aaye.

How do I extract a specific line from a text file in Unix?

Lati yọ awọn laini lọpọlọpọ jade, sọ awọn laini 2 si 4, o le ṣiṣẹ ọkan ninu awọn atẹle:

  1. $ sed -n 2,4p somefile. txt.
  2. $ 2,4! d' somefile. txt.

Kini NR ni aṣẹ awk?

NR ni a AWK-itumọ ti ni oniyipada ati awọn ti o tọka nọmba ti awọn igbasilẹ ti n ṣiṣẹ. Lilo: NR le ṣee lo ni iṣipopada iṣẹ duro nọmba ti laini ti n ṣiṣẹ ati pe ti o ba lo ni END o le tẹ nọmba awọn laini ti a ti ṣiṣẹ patapata. Apeere : Lilo NR lati tẹ nọmba laini sita ninu faili nipa lilo AWK.

How do I print a specific line using sed?

Ninu nkan yii ti jara sed, a yoo rii bii o ṣe le tẹ laini kan pato nipa lilo aṣẹ titẹ (p) ti sed. Bakanna, lati tẹ laini kan pato, fi nọmba ila ṣaaju 'p'. $ indicates the last line. !

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